1) Segment ED is a midsegment of ΔABC a) Reflexive Property b) Definition of congruent segments c) Definition of midsegment. d) Given 2) Segment AD≌Segment DB and Segment AE≌Segment EC. a) Segment Addition Postulate b) Division c) Given d) Definition of midsegment. 3) AD=DB and AE=EC a) Similar triangles have proportional sides b) SAS Similarity Theorem c) Addition d) Definition of congruent segments 4) AB=AD+DB and AC=AE+EC a) Segment Addition Postulate b) Addition c) Given d) Ratios of Corresponding Sides 5) If AB=AD+DB and AC=AE+EC, then AB=AD+AD and AC=AE+AE a) Addition b) Substitution c) Given d) Reflexive Property 6) If AB=AD+AD and AC=AE+AE, then AB=2AD and AC=2AE a) Given b) Substitution c) Segment Addition Postulate d) Addition 7) AB/AD=2AD/AD=2 and AC/AE=2AE/AE=2 a) Reflexive Property b) Definition of congruent segments c) Ratios of Corresponding Sides d) Substitution 8) <A≌<A a) Segment Addition Postulate b) Division c) Reflexive Property d) Given 9) △ABC∼△ADE a) Addition b) SAS Similarity Theorem c) Division d) Similar triangles have proportional sides 10) BC=2DE a) Similar triangles have proportional sides b) Division c) Segment Addition Postulate d) Given 11) If BC=2DE, then DE=(1/2)BC a) Reflexive Property b) SAS Similarity Theorem c) Addition d) Division
0%
Win or Lose Midsegment Theorem to Prove Similarity Lesson 25 Geo A
共享
由
Ameliaquinn
10th Grade
Math
Geometry
编辑内容
嵌入
更多
排行榜
显示更多
显示更少
此排行榜当前是私人享有。单击
,共享
使其公开。
资源所有者已禁用此排行榜。
此排行榜被禁用,因为您的选择与资源所有者不同。
还原选项
输赢测验
是一个开放式模板。它不会为排行榜生成分数。
需要登录
视觉风格
字体
需要订阅
选项
切换模板
显示所有
播放活动时将显示更多格式。
打开成绩
复制链接
QR 代码
删除
恢复自动保存:
?